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  4. Chlorine gas is prepared by reaction of H2SO4 with MnO2 and NaCl. What volume of Cl2 will be produced at STP if 50 g of NaCl is taken in the reaction?

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Q. Chlorine gas is prepared by reaction of $H_{2}SO_{4}$ with $MnO_{2}$ and NaCl. What volume of $Cl_{2}$ will be produced at STP if 50 g of NaCl is taken in the reaction?

NTA AbhyasNTA Abhyas 2020Some Basic Concepts of Chemistry

Solution:

$\underset{\underset{\left(2 \times 58.5 = 117 g\right)}{2 \text{ moles}}}{2 N a C l}+MnO_{2}+3H_{2}SO_{4} \rightarrow 2NaHSO_{4}+MnSO_{4}+\underset{\underset{22.4 \text{ L} \left(\text{STP}\right)}{1 \text{ mole}}}{C l_{2}}+2H_{2}O$

117 g of NaCl $\equiv 22.4$ L of $Cl_{2}$

50 g of $NaCl\equiv \frac{22.4}{117}\times 50=9.57$ L of $Cl_{2}$ at STP.