Question

Charge on an originally uncharged conductor is separated by holding a positively charged rod very closely nearby, as shown in figure. Assume that the induced negative charge on the conductor is equal to the positive charge $q$ on the rod. Then the flux through surface $S_1$ is

• A. zero
• B. $q/{\epsilon }_0$
• C. $-q/{\epsilon }_0$
• D. none of these

Answer 1

Answer: (B)

Net charge on the conductor will be zero. So, net charge inside $S_1$ will be the charge on the rod. Hence, flux through $S_1$ is $q/{\epsilon }_0$.