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  4. Charge on an originally uncharged conductor is separated by holding a positively charged rod very closely nearby, as shown in figure. Assume that the induced negative charge on the conductor is equal to the positive charge q on the rod. Then the flux through surface S1 is <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/c4376702c88a2ab3398571bfef44178d-.png />

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Q. Charge on an originally uncharged conductor is separated by holding a positively charged rod very closely nearby, as shown in figure. Assume that the induced negative charge on the conductor is equal to the positive charge $q$ on the rod. Then the flux through surface $S_{1}$ is
image

Electric Charges and Fields

Solution:

Net charge on the conductor will be zero. So, net charge inside $S_{1}$ will be the charge on the rod. Hence, flux through $S_{1}$ is $q / \varepsilon_{0}$.