Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
CH 3 CH = CHCH 3+ CHCl 3+t- BuOK arrow A ⋅ A is
Q.
C
H
3
C
H
=
C
H
C
H
3
+
C
H
C
l
3
+
t
−
B
u
O
K
→
A
⋅
A
is
1519
145
AIIMS
AIIMS 2008
Hydrocarbons
Report Error
A
6%
B
53%
C
35%
D
6%
Solution:
It is a method of preparation of cycloalkanes.
C
H
3
−
C
H
=
C
H
−
C
H
3
+
C
H
C
l
3
(
C
H
3
)
3
C
−
O
K