Q. $CH _{3} CH = CHCH _{3}+ CHCl _{3}+t- BuOK \rightarrow A \cdot A$ is
Solution:
It is a method of preparation of cycloalkanes.
$CH_3 - CH = CH -CH_3 + CHCl_3 \xrightarrow{(CH_3)_3C-OK }$
