Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
CH ≡ CH ->[O3/NaOH] X ->[Zn/CH3COOH]Y, Y is
Q.
C
H
≡
C
H
O
X
3
/
NaOH
X
Zn
/
CH
X
3
COOH
Y
,
Y
is
3415
235
Report Error
A
C
H
2
O
H
−
C
H
2
O
H
42%
B
C
H
3
−
C
H
2
O
H
35%
C
C
H
3
COO
H
19%
D
C
H
3
O
H
4%
Solution:
Correct answer is (a)
C
H
2
O
H
−
C
H
2
O
H
