1. Tardigrade
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  3. Chemistry
  4. CH ≡ CH ->[O3/NaOH] X ->[Zn/CH3COOH]Y, Y is

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Q. $CH \equiv CH \ce{->[O_3/NaOH]} X \ce{->[Zn/CH_3COOH]}Y, Y $is

Solution:

Correct answer is (a) $CH _{2} OH - CH _{2} OH$

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