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Tardigrade
Question
Chemistry
CH4 ->[Cl2/hv][1 eq] A->[Mg][dry ether]B->[(i)CO2][(ii)H3O+]C Product C in the above reaction is
Q.
C
H
4
C
l
2
/hv
1
eq
A
Mg
dry
ether
B
(
i
)
C
O
2
(
ii
)
H
3
O
+
C
Product
C
in the above reaction is
2620
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A
C
H
3
C
H
3
9%
B
C
H
3
C
H
2
O
H
35%
C
C
H
3
C
H
O
26%
D
C
H
3
COO
H
30%
Solution:
C
H
4
Cl
X
2
/
hv
1
eq
⋅
(
A
)
C
H
3
Cl
Mg
dry ether
(
B
)
C
H
3
M
g
Cl
CO
X
2
H
X
3
O
X
+
(
C
)
C
H
3
COO
H