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Q. $CH_4\ce{ ->[{Cl_2/hv}][{1\,eq}] A}\ce{->[{Mg}][{dry\,ether}]B}\ce{->[{(i)CO_2}][{(ii)H_3O^+}]C}$ Product $C$ in the above reaction is

Solution:

$CH_4 \ce{->[Cl_2/hv][1 eq.]} \underset{(A)}{CH_3Cl} \ce{->[Mg][\text{dry ether}]} \underset{(B)}{CH_3MgCl} \ce{->[CO_2][H_3O^+]} \underset{(C)}{CH_3COOH}$