CH 3- CH = CH 2+ HOBr longrightarrow P; The major product ' P ' is

Question

CH 3- CH = CH 2+ HOBr longrightarrow P; The major product ' P ' is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/cc44c81d8f676fab2699a0d23e0ab4b0-.png" /> HOBr Breaks as HO - Br longrightarrow underset( Nu -) H O- + underset( E +) Br + And alkene follows electrolphylic addition reaction. So, Br +attack at first and then OH attack.

Q. $C H_{3} - C H = C H_{2} + H OB r ⟶ P$ ; The major product ' $P$ ' is

HOBr Breaks as
$H O - B r ⟶ (N u^{-}) H (E^{+}) B r^{+}$
And alkene follows electrolphylic addition reaction. So, $B r^{+}$ attack at first and then $O H$ attack.

Q. CH3​−CH=CH2​+HOBr⟶P; The major product ' P ' is

HOBr Breaks as HO−Br⟶(Nu−)H​(E+)Br+​ And alkene follows electrolphylic addition reaction. So, Br+attack at first and then OH attack.

Q. $C H_{3} - C H = C H_{2} + H OB r ⟶ P$ ; The major product ' $P$ ' is

HOBr Breaks as
$H O - B r ⟶ (N u^{-}) H (E^{+}) B r^{+}$
And alkene follows electrolphylic addition reaction. So, $B r^{+}$ attack at first and then $O H$ attack.