Question

Calculate the unpaired electrons for a metal ion of first transition series having the magnetic moment of 2.83 BM.

• A. 6
• B. 4
• C. 3
• D. 2

Answer 1

Answer: (D)

$\mu =\sqrt{n(n+2)}$ ( magnetic moment)

( where n = no. of unpaired electron).

$2.83=\sqrt{n(n+2)}$

$n(n+2)=8$

$n^2+2n-8=0$

$n=2$ .