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Q. Calculate the unpaired electrons for a metal ion of first transition series having the magnetic moment of 2.83 BM.

NTA AbhyasNTA Abhyas 2020Coordination Compounds

Solution:

$\mu =\sqrt{n \left(\right. n + 2 \left.\right)}$ ( magnetic moment)

( where n = no. of unpaired electron).

$2.83=\sqrt{n \left(\right. n + 2 \left.\right)}$

$n\left(\right.n+2\left.\right)=8$

$n^{2}+2n-8=0$

$n=2$ .