Calculate the time required for complete decomposition of one mole of water using 2 ampere current. .

Question

Calculate the time required for complete decomposition of one mole of water using 2 ampere current. . (A) 9650 sec (B) 96500 sec (C) 1.93 × 105 sec (D) 38600 sec

Tardigrade Admin · Accepted Answer

2 H 2 O arrow 2 H 2+ O 2 One mole of H 2 O need 2 moles of e - s for electrolysis. So, Q=I× t ⇒ t =( Q / I ) =(2 × 96500/2) ∴ t =96500 sec

Q. Calculate the time required for complete decomposition of one mole of water using $2$ ampere current. .

$9650 sec$

$96500 sec$

$1.93 \times 1 0^{5} sec$

$38600 sec$

$2 H_{2} O \to 2 H_{2} + O_{2}$
One mole of $H_{2} O$ need 2 moles of $e^{-} s$ for electrolysis.
So, $Q = I \times t$
$\Rightarrow t = \frac{Q}{I}$
$= \frac{2 \times 96500}{2}$
$∴ t = 96500 sec$

Q. Calculate the time required for complete decomposition of one mole of water using 2 ampere current. .

9650sec

96500sec

1.93×105sec

38600sec