Calculate the ratio of current flowing through the battery at t=0 and t=∈ fty . ( t=0 is the time of closing of the switch)

Question

Calculate the ratio of current flowing through the battery at t=0 and t=∈ fty . ( t=0 is the time of closing of the switch) <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-lqkkxnqqpwjt.png" /> (A) 1 (B) 2 (C) (1/2) (D) 0

Tardigrade Admin · Accepted Answer

At t=0 capacitor is short circuit and inductor is open circuit. Solution

i1=(20/5 + 5)=2A At t=∈ fty capacitor is open circuit and inductor is a short circuit. Solution

i2=(20/5 + 5)=2 A ∴ (i1/i2)=(2/2)=1

Q. Calculate the ratio of current flowing through the battery at $t = 0$ and $t =\in f t y$ . ( $t = 0$ is the time of closing of the switch)

$1$

$2$

$\frac{1}{2}$

$0$

At $t = 0$ capacitor is short circuit and inductor is open circuit.

$i_{1} = \frac{20}{5 + 5} = 2 A$
At $t =\in f t y$ capacitor is open circuit and inductor is a short circuit.

$i_{2} = \frac{20}{5 + 5} = 2 A$
$∴ \frac{i _{1}}{i _{2}} = \frac{2}{2} = 1$

Q. Calculate the ratio of current flowing through the battery at t=0 and t=∈fty . ( t=0 is the time of closing of the switch)

1

2

21​

0

At t=0 capacitor is short circuit and inductor is open circuit. i1​=5+520​=2A At t=∈fty capacitor is open circuit and inductor is a short circuit. i2​=5+520​=2A ∴i2​i1​​=22​=1

Q. Calculate the ratio of current flowing through the battery at $t = 0$ and $t =\in f t y$ . ( $t = 0$ is the time of closing of the switch)

$1$

$2$

$\frac{1}{2}$

$0$

At $t = 0$ capacitor is short circuit and inductor is open circuit.

$i_{1} = \frac{20}{5 + 5} = 2 A$
At $t =\in f t y$ capacitor is open circuit and inductor is a short circuit.

$i_{2} = \frac{20}{5 + 5} = 2 A$
$∴ \frac{i _{1}}{i _{2}} = \frac{2}{2} = 1$