Calculate the overall complex dissociation equilibrium constant for the [Cu(NH3)4]2+ ions, given that stability constant (β4) for this complex is 2.1 × 1013.

Question

Calculate the overall complex dissociation equilibrium constant for the [Cu(NH3)4]2+ ions, given that stability constant (β4) for this complex is 2.1 × 1013. (A) 8.27 × 10-13 (B) 4.76 × 10-14 (C) 2.39 × 10-7 (D) 1.83 × 1014

Tardigrade Admin · Accepted Answer

Dissociation constant is the reciprocal of the stability constant (β = 1/K). Overall complex dissociation equilibrium constant, K = (1/β4) =(1/2.1×1013)=4.76×10-14

Q. Calculate the overall complex dissociation equilibrium constant for the $[C u (N H_{3})_{4}]^{2 +}$ ions, given that stability constant ( $β$ ₄) for this complex is $2.1 \times 1 0^{13}$ .

$8.27 \times 1 0^{- 13}$

$4.76 \times 1 0^{- 14}$

$2.39 \times 1 0^{- 7}$

$1.83 \times 1 0^{14}$

Dissociation constant is the reciprocal of the stability constant ( $β$ = 1/K).
Overall complex dissociation equilibrium
constant, $K = \frac{1}{β _{4}}$
$= \frac{1}{2.1 \times 1 0 ^{13}} = 4.76 \times 1 0^{- 14}$

Q. Calculate the overall complex dissociation equilibrium constant for the [Cu(NH3​)4​]2+ ions, given that stability constant (β4) for this complex is 2.1×1013.

8.27×10−13

4.76×10−14

2.39×10−7

1.83×1014