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Chemistry
Calculate the overall complex dissociation equilibrium constant for the [Cu(NH3)4]2+ ions, given that stability constant (β4) for this complex is 2.1 × 1013.
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Q. Calculate the overall complex dissociation equilibrium constant for the $[Cu(NH_3)_4]^{2+}$ ions, given that stability constant ($\beta$
4
) for this complex is $2.1 \times 10^{13}$.
AIIMS
AIIMS 2017
Coordination Compounds
A
$8.27 \times 10^{-13}$
11%
B
$4.76 \times 10^{-14}$
77%
C
$2.39 \times 10^{-7}$
9%
D
$1.83 \times 10^{14}$
3%
Solution:
Dissociation constant is the reciprocal of the stability constant ($\beta$ = 1/K).
Overall complex dissociation equilibrium
constant, $K = \frac{1}{\beta_{4}}$
$\quad\quad\quad=\frac{1}{2.1\times10^{13}}=4.76\times10^{-14}$