Calculate the osmotic pressure of a solution containing 0.153 g glucose in 0.1 L of the solution at 298 K?

Question

Calculate the osmotic pressure of a solution containing 0.153 g glucose in 0.1 L of the solution at 298 K? (A) 0.027 atm (B) 0.107 atm (C) 0.172 atm (D) 0.207 atm

Tardigrade Admin · Accepted Answer

π =(nRT/V)=(WRT/MV) =(0.153× 0.082× 298/180× 0.1)=0.207 atm

Q. Calculate the osmotic pressure of a solution containing $0.153 g$ glucose in $0.1 L$ of the solution at $298 K$ ?

0.027 atm

0.107 atm

0.172 atm

0.207 atm

$π = \frac{n RT}{V} = \frac{W RT}{M V}$
$= \frac{0.153 \times 0.082 \times 298}{180 \times 0.1} = 0.207 a t m$

Q. Calculate the osmotic pressure of a solution containing 0.153g glucose in 0.1L of the solution at 298K?