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Q. Calculate the osmotic pressure of a solution containing $0.153 \,g$ glucose in $0.1 \,L$ of the solution at $298 \,K$?

J & K CETJ & K CET 2001

Solution:

$ \pi =\frac{nRT}{V}=\frac{WRT}{MV} $
$ =\frac{0.153\times 0.082\times 298}{180\times 0.1}=0.207\,atm $