Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Calculate the mole fraction of ethylene glycol ( C 2 H 6 O 2) in an aqueous solution containing 20 % of C 2 H 6 O 2 by mass.
Q. Calculate the mole fraction of ethylene glycol
(
C
2
H
6
O
2
)
in an aqueous solution containing
20%
of
C
2
H
6
O
2
by mass.
2075
184
Solutions
Report Error
A
0.68
0%
B
0.068
88%
C
0.932
0%
D
0.0932
12%
Solution:
Weight of
C
2
H
6
O
2
=
20
Molecular mass of
C
2
H
6
O
2
=
2
×
12
+
6
+
16
×
2
=
62
Weight of water
=
100
−
20
=
80
Mole fraction of
C
2
H
6
O
2
=
62
20
+
18
80
62
20
=
0.322
+
4.44
0.322
=
4.77
0.322
=
0.068