Calculate the mole fraction of ethylene glycol ( C 2 H 6 O 2) in an aqueous solution containing 20 % of C 2 H 6 O 2 by mass.

Question

Calculate the mole fraction of ethylene glycol ( C 2 H 6 O 2) in an aqueous solution containing 20 % of C 2 H 6 O 2 by mass. (A) 0.68 (B) 0.068 (C) 0.932 (D) 0.0932

Tardigrade Admin · Accepted Answer

Weight of C 2 H 6 O 2=20 Molecular mass of C 2 H 6 O 2 =2 × 12+6+16 × 2=62 Weight of water =100-20=80 Mole fraction of C 2 H 6 O 2 =((20/62)/(20)62+(80)18 =(0.322/0.322+4.44) =(0.322/4.77)=0.068

Q. Calculate the mole fraction of ethylene glycol (C2​H6​O2​) in an aqueous solution containing 20% of C2​H6​O2​ by mass.

0.68

0.068

0.932

0.0932

Weight of C2​H6​O2​=20 Molecular mass of C2​H6​O2​ =2×12+6+16×2=62 Weight of water =100−20=80 Mole fraction of C2​H6​O2​ =6220​+1880​6220​​ =0.322+4.440.322​ =4.770.322​=0.068

Q. Calculate the mole fraction of ethylene glycol $(C_{2} H_{6} O_{2})$ in an aqueous solution containing $20%$ of $C_{2} H_{6} O_{2}$ by mass.