Calculate the molarity of NaOH solution prepared by dissolving 0.4 g of NaOH in enough water to form 500 ml of the solution

Question

Calculate the molarity of NaOH solution prepared by dissolving 0.4 g of NaOH in enough water to form 500 ml of the solution (A) 0.02 (B) 0.05 (C) 0.04 (D) 0.03

Tardigrade Admin · Accepted Answer

Molarity =(wB g L-1/MB g m o l-1) =((0.4/500) × 100/40)=0.02 M [∴ wB= text mass of solute ( NaOH )=0.4 g / mL . .MB= text molar mass of NaOH =40 gmol -1]

Q. Calculate the molarity of $N a O H$ solution prepared by dissolving $0.4 g$ of $N a O H$ in enough water to form $500 m l$ of the solution

$0.02$

$0.05$

$0.04$

$0.03$

Molarity $= \frac{w _{B} g L ^{- 1}}{M _{B} g m o l ^{- 1}}$
$= \frac{\frac{0.4}{500} \times 100}{40} = 0.02 M$
$[∴ w_{B} = mass of solute (N a O H) = 0.4 g / m L < b r / > M_{B} = molar mass of N a O H = 40 g m o l^{- 1}]$

Q. Calculate the molarity of NaOH solution prepared by dissolving 0.4g of NaOH in enough water to form 500ml of the solution

0.02

0.05

0.04

0.03