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Q. Calculate the molarity of $NaOH$ solution prepared by dissolving $0.4\, g$ of $NaOH$ in enough water to form $500\, ml$ of the solution

AP EAMCETAP EAMCET 2020

Solution:

Molarity $=\frac{w_{B} g L^{-1}}{M_{B} g m o l^{-1}}$
$=\frac{\frac{0.4}{500} \times 100}{40}=0.02 M$
${\left[\therefore w_{B}=\text { mass of solute }( NaOH )=0.4 g / mL \right.}
\left.M_{B}=\text { molar mass of } NaOH =40 gmol ^{-1}\right]$