Calculate the molality of the solution prepared by dissolving 18 g of glucose (mol mass = 180) in 500 gm of water

Question

Calculate the molality of the solution prepared by dissolving 18 g of glucose (mol mass = 180) in 500 gm of water (A) 0.2 M (B) 0.4 M (C) 2.2 M (D) 0.5 M

Tardigrade Admin · Accepted Answer

Moles of glucose =( text mass / text Molecular mass )=(18/180) ⇒ Molality =(0.1/500) × 1000=0.2 M

Q. Calculate the molality of the solution prepared by dissolving $18 g$ of glucose (mol mass = 180) in $500 g m$ of water

0.2 M

0.4 M

2.2 M

0.5 M

Moles of glucose $= \frac{mass}{Molecular mass} = \frac{18}{180}$

$\Rightarrow$ Molality $= \frac{0.1}{500} \times 1000 = 0.2 M$

Q. Calculate the molality of the solution prepared by dissolving 18g of glucose (mol mass = 180) in 500gm of water