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  4. Calculate the molality of the solution prepared by dissolving 18 g of glucose (mol mass = 180) in 500 gm of water

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Q. Calculate the molality of the solution prepared by dissolving $18\, g$ of glucose (mol mass = 180) in $500\, gm$ of water

AIIMSAIIMS 1995Solutions

Solution:

Moles of glucose $=\frac{\text { mass }}{\text { Molecular mass }}=\frac{18}{180}$

$\Rightarrow $ Molality $=\frac{0.1}{500} \times 1000=0.2 \,M$