Calculate the molality of solution containing 3 g glucose dissolved in 30 g of water. (molar mass of glucose =180 )

Question

Calculate the molality of solution containing 3 g glucose dissolved in 30 g of water. (molar mass of glucose =180 ) (A) 0.50 m (B) 0.56 m (C) 0.091 m (D) 0.05 m

Tardigrade Admin · Accepted Answer

Molality =( text moles of solute /w t text of solvent ( kg ))=( n B / w A ( kg )) w B =3 g, w A =30 g Molarity ( m )=((3/180)/30) × 1000 =(1/1800) × 1000=0.56 m

Q. Calculate the molality of solution containing $3 g$ glucose dissolved in $30 g$ of water. (molar mass of glucose $= 180$ )

0.50 m

0.56 m

0.091 m

0.05 m

Molality $= \frac{moles of solute}{wt of solvent ( k g )} = \frac{n _{B}}{w _{A} ( k g )}$
$w_{B} = 3 g, w_{A} = 30 g$
Molarity $(m) = \frac{\frac{3}{180}}{30} \times 1000$
$= \frac{1}{1800} \times 1000 = 0.56 m$

Q. Calculate the molality of solution containing 3g glucose dissolved in 30g of water. (molar mass of glucose =180 )