Calculate the minimum mass of C l2 in grams required to produce text37 text.25 textg textKCl? Cl2+2KOH arrow KCl+KClO+H2O

Question

Calculate the minimum mass of C l2 in grams required to produce text37 text.25 textg textKCl? Cl2+2KOH arrow KCl+KClO+H2O (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Cl2+2KOH arrow KCl+KClO+H2O text37 text.25 textg (37.25/74.5)mol 0.5 mol KCl Mole of C l2 required = text0 text.5 textmol Mass of C l2 required =0.5× 71=35.5 g

Q. Calculate the minimum mass of $C l_{2}$ in grams required to produce $37 .25 g KCl?$

$C l_{2} + 2 K O H \to K Cl + K ClO + H_{2} O$

$C l_{2} + 2 K O H \to K Cl + K ClO + H_{2} O$

$37 .25 g$

$\frac{37.25}{74.5} m o l$

$0.5 m o l K Cl$

Mole of $C l_{2}$ required = $0 .5 mol$

Mass of $C l_{2}$ required $= 0.5 \times 71 = 35.5 g$

Q. Calculate the minimum mass of Cl2​ in grams required to produce 37.25gKCl? Cl2​+2KOH→KCl+KClO+H2​O

Cl2​+2KOH→KCl+KClO+H2​O 37.25g 74.537.25​mol 0.5molKCl Mole of Cl2​ required = 0.5mol Mass of Cl2​ required =0.5×71=35.5g

Q. Calculate the minimum mass of $C l_{2}$ in grams required to produce $37 .25 g KCl?$

$C l_{2} + 2 K O H \to K Cl + K ClO + H_{2} O$

$C l_{2} + 2 K O H \to K Cl + K ClO + H_{2} O$

$37 .25 g$

$\frac{37.25}{74.5} m o l$

$0.5 m o l K Cl$

Mole of $C l_{2}$ required = $0 .5 mol$

Mass of $C l_{2}$ required $= 0.5 \times 71 = 35.5 g$