Question

Calculate the minimum mass of $C l_{2}$ in grams required to produce $\text{37} \text{.25} \, \text{g} \, \text{KCl?}$

$Cl_{2}+2KOH \rightarrow KCl+KClO+H_{2}O$

Answer 1

$Cl_{2}+2KOH \rightarrow KCl+KClO+H_{2}O$

$\text{37} \text{.25} \, \text{g}$

$\frac{37.25}{74.5}mol$

$0.5 \, mol \, KCl$

Mole of $C l_{2}$ required = $\text{0} \text{.5} \, \text{mol}$

Mass of $C l_{2}$ required $=0.5\times 71=35.5 \, g$