Calculate the mean % error in five observations: 80.0, 80.5, 81.0, 81.5, 82

Question

Calculate the mean % error in five observations: 80.0, 80.5, 81.0, 81.5, 82 (A) 0.74% (B) 1.74% (C) 0.38% (D) 1.38%

Tardigrade Admin · Accepted Answer

Mean of the errors = (80+80.5+81+81.5+82/5)=81 |80 - 81| = 1 |80.5 - 81| = 0.5 |81 - 81| = 0 |81.5 - 81| = 0.5 |82 - 81| = 1 Mean error =(1+0.5+0+0.5+1/5)=0.6 % errors =(0.6/81)×100=0.74 %

Q. Calculate the mean % error in five observations :
80.0, 80.5, 81.0, 81.5, 82

0.74%

1.74%

0.38%

1.38%

Mean of the errors = $\frac{80 + 80.5 + 81 + 81.5 + 82}{5} = 81$
|80 - 81| = 1
|80.5 - 81| = 0.5
|81 - 81| = 0
|81.5 - 81| = 0.5
|82 - 81| = 1
Mean error $= \frac{1 + 0.5 + 0 + 0.5 + 1}{5} = 0.6$
$%$ errors = $\frac{0.6}{81} \times 100 = 0.74%$

Q. Calculate the mean % error in five observations : 80.0, 80.5, 81.0, 81.5, 82