Question

Calculate the deposited mass of silver which is plotted against charge in electrolysis of silver nitrate.



Slope of the line gives:

• A. The equivalent mass of silver
• B. Electrochemical equivalent of silver
• C. The value of Faraday
• D. The current passed through the cell

Answer 1

Answer: (B)

According to Faraday's $1^{\text{st }}$ law of electrolysis.

$\text{W}\propto \text{Q}$

$\text{W}=\text{Z}.\text{Q}$

$\because \text{Z}=\frac{\text{E}}{\text{F}}$

then

$\text{W}=\frac{QE}{\text{F}}$ or $\frac{\text{E}}{\text{F}}.\text{Q}$

Compare with straight line equation

$\text{Y}=\text{mx}+\text{c}$ [ $\text{m}=$ slope of line]

$\because \text{c}=0,$ passing through origin

Slope of the line $\left(\text{m}\right)=\frac{\text{E}}{\text{F}}=Z$ (Electrochemical equivalent of silver)

Slope $=\frac{E}{F}$