Question

Calculate the angular momentum of an electron in 'd' orbital .

• A. $\sqrt{6}\hslash$
• B. $\sqrt{2}\hslash$
• C. $2\sqrt{3}\hslash$
• D. $0\hslash$

Answer 1

Answer: (A)

For d-electrons l=2
Angular orbital momentum $=\sqrt{l(l+1)}\frac{h}{2\pi }$
$=\sqrt{6}\frac{h}{2\pi }=\sqrt{6}\hslash$
$\therefore \frac{h}{2\pi }=\hslash$