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Chemistry
Calculate the angular momentum of an electron in 'd' orbital .
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Q. Calculate the angular momentum of an electron in 'd' orbital .
NTA Abhyas
NTA Abhyas 2020
A
$\sqrt{6}ℏ$
B
$\sqrt{2} \, ℏ$
C
$2\sqrt{3} \, ℏ$
D
$0 \, ℏ$
Solution:
For d-electrons l=2
Angular orbital momentum $=\sqrt{l \left(\right. l + 1 \left.\right)}\frac{h}{2 \pi }$
$=\sqrt{6}\frac{h}{2 \pi }=\sqrt{6}ℏ$
$\therefore \frac{h}{2 \pi }=ℏ$