Question

Calculate standard free energy change for the reaction $2Ag+2H^{+}\to H_2+2A{g}^{+}$

Given: $E_{A{g}^{+}/Ag}^o=+0.80V$

• A. 308.08 kJ
• B. 154.4 kJ
• C. 77.2 kJ
• D. - 154.4 kJ

Answer 1

Answer: (B)

$E_{cell}^o=E_{H_2}^o-E_{Ag}^o$

$=0-0.80=-0.80$

$\Delta G^{\circ }=-nF{E}_{cell}^o$

$=-2\times 96500\times (-0.8)$

$=+154.4kJ$