Question

Calculate standard free energy change for the reaction $2Ag+2H^{+} \rightarrow H_{2}+2Ag^{+}$

Given: $E_{A g^{+} / A g}^{o}=+0.80V$

• A. 308.08 kJ
• B. 154.4 kJ
• C. 77.2 kJ
• D. - 154.4 kJ

Answer 1

Answer: (B)

$E_{c e l l}^{o}=E_{H_{2}}^{o}-E_{A g}^{o}$

$=0-0.80=-0.80$

$\Delta G^\circ =-nFE_{c e l l}^{o}$

$=-2\times 96500\times \left(\right.-0.8\left.\right)$

$=+154.4 \, kJ$