Calculate resonance enthalpy of (CO)2(g) from the following data: Δ HC° C(. text graphite .)=-390kJ(mol)- 1 Δ HS° C(. text graphite .)=715kJ(mol)- 1 Δ HBE° [.O=O].=500kJmol- 1 Δ HBE° [.C=O].=875kJmol- 1

Question

Calculate resonance enthalpy of (CO)2(g) from the following data: Δ HC° C(. text graphite .)=-390kJ(mol)- 1 Δ HS° C(. text graphite .)=715kJ(mol)- 1 Δ HBE° [.O=O].=500kJmol- 1 Δ HBE° [.C=O].=875kJmol- 1 (A) -40kJmol- 1 (B) -145kJmol- 1 (C) -72.5kJmol- 1 (D) -290kJmol- 1

Tardigrade Admin · Accepted Answer

C(.s.)+O2(.g.) arrow (CO)2(.g.) 715+500-1750-R.E.=-390 R.E=-145kJmol- 1

Q. Calculate resonance enthalpy of $(CO)_{2} (g)$ from the following data:
$Δ H_{C}^{\circ} C (graphite) = - 390 k J (m o l)^{- 1}$
$Δ H_{S}^{\circ} C (graphite) = 715 k J (m o l)^{- 1}$
$Δ H_{BE}^{\circ} [O = O] = 500 k J m o l^{- 1}$
$Δ H_{BE}^{^{\circ}} [C = O] = 875 k J m o l^{- 1}$

$- 40 k J m o l^{- 1}$

$- 145 k J m o l^{- 1}$

$- 72.5 k J m o l^{- 1}$

$- 290 k J m o l^{- 1}$

$C (s) + O_{2} (g) \to (CO)_{2} (g)$
$715 + 500 - 1750 - R . E . = - 390$
$R . E = - 145 k J m o l^{- 1}$

Q. Calculate resonance enthalpy of (CO)2​(g) from the following data: ΔHC∘​C( graphite )=−390kJ(mol)−1 ΔHS∘​C( graphite )=715kJ(mol)−1 ΔHBE∘​[O=O]=500kJmol−1 ΔHBE∘​[C=O]=875kJmol−1

−40kJmol−1

−145kJmol−1

−72.5kJmol−1

−290kJmol−1