Calculate relative rate of effusion of O2 to CH4 through a container containing textO2 and CH4 in 3:2 mass ratio :-

Question

Calculate relative rate of effusion of O2 to CH4 through a container containing textO2 and CH4 in 3:2 mass ratio :- (A) (3 √2/4) (B) (3/4 √2) (C) (3/2 √2) (D) none of these

Tardigrade Admin · Accepted Answer

(rO2/rCH4)=(nO2/nCH4)=√(MCH4/MO2) =(3/2)× (16/32)× √(16/32)=(3/4 √2)

Q. Calculate relative rate of effusion of $O_{2}$ to $C H_{4}$ through a container containing $O_{2}$ and $C H_{4}$ in $3 : 2$ mass ratio :-

$\frac{3 2}{4}$

$\frac{3}{4 2}$

$\frac{3}{2 2}$

none of these

$\frac{r _{O_{2}}}{r _{C H_{4}}} = \frac{n _{O_{2}}}{n _{C H_{4}}} = \frac{M _{C H_{4}}}{M _{O_{2}}}$
$= \frac{3}{2} \times \frac{16}{32} \times \frac{16}{32} = \frac{3}{4 2}$

Q. Calculate relative rate of effusion of O2​ to CH4​ through a container containing O2​ and CH4​ in 3:2 mass ratio :-

432​​

42​3​

22​3​