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Q. Calculate relative rate of effusion of $O_{2}$ to $CH_{4}$ through a container containing $\text{O}_{2}$ and $CH_{4}$ in $3:2$ mass ratio :-

NTA AbhyasNTA Abhyas 2022

Solution:

$\frac{r_{O_{2}}}{r_{CH_{4}}}=\frac{n_{O_{2}}}{n_{CH_{4}}}=\sqrt{\frac{M_{CH_{4}}}{M_{O_{2}}}}$
$=\frac{3}{2}\times \frac{16}{32}\times \sqrt{\frac{16}{32}}=\frac{3}{4 \sqrt{2}}$