Calculate normality of the mixture obtained by mixing 100 ml of 0.1 N HCl and 50 ml of 0.25 N NaOH solution

Question

Calculate normality of the mixture obtained by mixing 100 ml of 0.1 N HCl and 50 ml of 0.25 N NaOH solution (A) 0.0467 N (B) 0.0367 N (C) 0.0267 N (D) 0.0167 N

Tardigrade Admin · Accepted Answer

Meq. of HCl=100 × 0.1=10 Meq. of NaOH =50 × 0.25=12.5 ∴ HCl and NaOH neutralize each other with equal eq Meq. of NaOH left =12.5-10=2.5 Volume of new solution =100+50=150 ml NNaoH left =(2.5/150)-0.0167 N Hence normality of the mixture obtained is 0.0167 N

Q. Calculate normality of the mixture obtained by mixing 100 ml of 0.1 N HCl and 50 ml of 0.25 N NaOH solution

$0.0467 N$

$0.0367 N$

$0.0267 N$

$0.0167 N$

Q. Calculate normality of the mixture obtained by mixing 100 ml of 0.1 N HCl and 50 ml of 0.25 N NaOH solution

0.0467N

0.0367N

0.0267N

0.0167N

Meq. of HCl=100×0.1=10 Meq. of NaOH=50×0.25=12.5 ∴ HCl and NaOH neutralize each other with equal eq Meq. of NaOH left =12.5−10=2.5 Volume of new solution =100+50=150ml NNaoH​ left =1502.5​−0.0167N Hence normality of the mixture obtained is 0.0167 N

$0.0467 N$

$0.0367 N$

$0.0267 N$

$0.0167 N$