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Q.
Calculate normality of the mixture obtained by mixing 100 ml of 0.1 N HCl and 50 ml of 0.25 N NaOH solution
Solutions
Solution:
Meq. of $HCl=100 \times 0.1=10$
Meq. of $NaOH =50 \times 0.25=12.5$
$\therefore $ HCl and NaOH neutralize each other with equal eq
Meq. of NaOH left $=12.5-10=2.5$
Volume of new solution
$=100+50=150\,ml$
$N_{NaoH}$ left $=\frac{2.5}{150}-0.0167\,N$
Hence normality of the mixture obtained is 0.0167 N