Calculate Kc for the reversible process given below if Kp = 167 and T = 800°C. CaCO3(s) leftharpoons CaO(s) + CO2(g)

Question

Calculate Kc for the reversible process given below if Kp = 167 and T = 800°C. CaCO3(s) leftharpoons CaO(s) + CO2(g) (A) 1.95 (B) 1.85 (C) 1.89 (D) 1.60

Tardigrade Admin · Accepted Answer

Kp=Kc(RT)Δ n Δ n=np-nR=1 167=Kc(0.0821×1073) Kc=(167/0.0821×1073)=1.89

Q. Calculate $K_{c}$ for the reversible process given below if $K_{p} = 167$ and $T = 80 0^{°} C$ .
$C a C O_{3 (s)} ⇌ C a O_{(s)} + C O_{2 (g)}$

$1.95$

$1.85$

$1.89$

$1.60$

$K_{p} = K_{c} (RT)^{Δ n}$
$Δ n = n_{p} - n_{R} = 1$
$167 = K_{c} (0.0821 \times 1073)$
$K_{c} = \frac{167}{0.0821 \times 1073} = 1.89$

Q. Calculate Kc​ for the reversible process given below if Kp​=167 and T=800°C. CaCO3(s)​⇌CaO(s)​+CO2(g)​

1.95

1.85

1.89

1.60