Question

Calculate $K_c$ for the reversible process given below if $K_p = 167$ and $T = 800^°C$.
$CaCO_{3(s)} \rightleftharpoons CaO_{(s)} + CO_{2(g)}$

• A. $1.95$
• B. $1.85$
• C. $1.89$
• D. $1.60$

Answer 1

Answer: (C)

$K_{p}=K_{c}\left(RT\right)^{\Delta n}$
$\Delta n=n_{p}-n_{R}=1$
$167=K_{c}\left(0.0821\times1073\right)$
$K_{c}=\frac{167}{0.0821\times1073}=1.89$