Question

Calculate change in internal energy if $\Delta H=-92.2kJ,P=40atm$ and $\Delta V=-1L.$

• A. -42 kJ
• B. -88 kJ
• C. +88 kJ
• D. +42 kJ

Answer 1

Answer: (B)

$\Delta H=\Delta E+P\Delta V$

$\Delta E=\Delta H-P\Delta V=-92.2-40\times \left(-1\right)\times 101\times 10^{-3}$

$=-92.2+4.04=-88.16kJ\approx -88kJ.$