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  3. Chemistry
  4. Calculate change in internal energy if Δ H=- 92.2 kJ, P = 40 atm and Δ V= -1 L.

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Q. Calculate change in internal energy if $\Delta H=- 92.2\, kJ,\, P = 40\, atm$ and $\Delta V= -1\,L.$

AIIMSAIIMS 2007Thermodynamics

Solution:

$\Delta H=\Delta E+P\Delta V$

$\Delta E=\Delta H-P\Delta V=-92.2-40\times\left(-1\right)\times101\times10^{-3}$

$=-92.2+4.04=-88.16\,kJ \approx-88\,kJ.$