Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of CO2 will be obtained by thermal decomposition of 50 g of CaCO3?

Question

Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of CO2 will be obtained by thermal decomposition of 50 g of CaCO3? (A) 1 L (B) 11.2 L (C) 44 L (D) 22.4 L

Tardigrade Admin · Accepted Answer

underset text100 gCaCO3 → CaO + underset text1 mole = 22.4 LCO2 100 g of CaCO3 at STP gives 22.4 L of CO 2 50 g of CaCO3 will produce (22.4/100)×50 = 11.2 L of CO2

Q. Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of $C O_{2}$ will be obtained by thermal decomposition of $50 g$ of $C a C O_{3}$ ?

$1 L$

$11.2 L$

$44 L$

$22.4 L$

$100 g C a C O_{3} \to C a O + 1 mole = 22.4 L C O_{2}$
$100 g$ of $C a C O_{3}$ at $STP$ gives $22.4 L$ of $C O_{2}$
$50 g$ of $C a C O_{3}$ will produce $\frac{22.4}{100} \times 50$
$= 11.2 L$ of $C O_{2}$

Q. Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of CO2​ will be obtained by thermal decomposition of 50g of CaCO3​?

1L

11.2L

44L

22.4L