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Tardigrade
Question
Chemistry
C6H6 xrightarrow[H2SO4]HNO3 X xrightarrow[FeCl3]Cl2 Y . In the above sequence Y can be
Q.
C
6
H
6
H
N
O
3
H
2
S
O
4
X
C
l
2
F
e
C
l
3
Y
.
In the above sequence
Y
can be
4136
177
AIIMS
AIIMS 1999
Hydrocarbons
Report Error
A
3-nitrochlorobenzene
41%
B
1-nitrochlorobenzene
25%
C
4-nitrochlorobenzene
23%
D
none of these
11%
Solution:
(
H
N
O
3
+
H
2
S
O
4
)
reagent is the agent for nitration in aromatic rings.
H
N
O
3
+
2
H
2
S
O
4
→
N
O
2
+
+
H
S
O
4
−
+
H
3
O
+
—
N
O
2
group is a meta directing group so chlorine atom goes to meta position of the ring.