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  4. C6H6 xrightarrow[H2SO4]HNO3 X xrightarrow[FeCl3]Cl2 Y . In the above sequence Y can be

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Q. $ C_6H_6 \xrightarrow[{H_2SO_4}]{HNO_3} X \xrightarrow[{FeCl_3}]{Cl_2} Y $.
In the above sequence $Y$ can be

AIIMSAIIMS 1999Hydrocarbons

Solution:

$(HNO_3 + H_2SO_4)$ reagent is the agent for nitration in aromatic rings.
$HNO_3 + 2H_2SO_4 \to NO_2^+ + HSO_4^- + H_3O^+$
$—NO_2$ group is a meta directing group so chlorine atom goes to meta position of the ring.

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