C6H5-CH=CHCHO -[X] C6H5CH= CHCH2OH . In the above sequence X can be:

Question

C6H5-CH=CHCHO ->[X] C6H5CH= CHCH2OH . In the above sequence X can be: (A)  H2/Ni  (B) NaBH4 (C)  K2Cr2O7/H+  (D) both [a] and [b]

Tardigrade Admin · Accepted Answer

NaBH4 and LiAIH4 attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond. underset text Cinnamic aldehyde C6H5-CH= CHCHO ->[NaBH4] underset text Cinnamic alcohol C6H5-CH= CH.CH2OH

Q. $C X_{6} H X_{5} - CH = CHCHO X C X_{6} H X_{5} CH = CHCH X_{2} OH$ . In the above sequence X can be:

$H_{2} / N i$

$N a B H_{4}$

$K_{2} C r_{2} O_{7} / H^{+}$

both [a] and [b]

$N a B H_{4}$ and $L i A I H_{4}$ attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond.
$Cinnamic aldehyde C X_{6} H X_{5} - CH = CHCHO NaBH X_{4} Cinnamic alcohol C X_{6} H X_{5} - CH = CH \cdot CH X_{2} OH$

Q. CX6​HX5​−CH=CHCHOX​CX6​HX5​CH= CHCHX2​OH . In the above sequence X can be:

H2​/Ni

NaBH4​

K2​Cr2​O7​/H+