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Q. $\ce{ C6H5-CH=CHCHO ->[X] C6H5CH= CHCH2OH }$ . In the above sequence X can be:

ManipalManipal 2005

Solution:

$NaBH_4$ and $LiAIH_4$ attacks only carbonyl group and reduce it into alcohol group. They do not attack on double bond.
$\ce{ $\underset{\text{ Cinnamic aldehyde }}{\ce{ C6H5-CH= CHCHO }}$ ->[\ce{NaBH_4}] $\underset{\text{ Cinnamic alcohol }}{\ce{ C6H5-CH= CH.CH2OH }}$ } $