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Tardigrade
Question
Chemistry
CH3-CH=CH2+HBr xrightarrow[]A; compound A is
Q.
C
H
3
−
C
H
=
C
H
2
+
H
B
r
A
;
compound A is
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A
∣
B
r
C
H
2
−
C
H
=
C
H
2
B
C
H
3
−
C
H
2
−
C
H
2
B
r
C
C
H
3
−
∣
B
r
C
H
−
C
H
3
D
∣
B
r
C
H
2
−
C
H
2
−
∣
B
r
C
H
2
Solution:
p
ro
p
e
n
e
C
H
3
−
C
H
=
C
H
2
+
H
B
r
→
2
−
b
ro
m
o
p
ro
p
an
e
C
H
3
−
∣
B
r
C
H
−
C
H
3