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Chemistry
CH3-CH=CH2+HBr xrightarrow[]A; compound A is
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Q. $ C{{H}_{3}}-CH=C{{H}_{2}}+HBr\xrightarrow[{}]{{}}A; $ compound A is
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Rajasthan PET 2003
A
$ \underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,-CH=C{{H}_{2}} $
B
$ C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}Br $
C
$ C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}} $
D
$ \underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\, $
Solution:
$ \underset{propene}{\mathop{C{{H}_{3}}-CH=C{{H}_{2}}}}\,+HBr\to \underset{2\text{ }-bromo\text{ }propane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}}}\, $