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Tardigrade
Question
Chemistry
C 6 H 5 ⋅ CH 3 xrightarrow[H2SO4] K 2 Cr 2 O 7Y, Here Y is:
Q.
C
6
H
5
⋅
C
H
3
K
2
C
r
2
O
7
H
2
S
O
4
Y
, Here
Y
is:
2965
229
JIPMER
JIPMER 2002
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A
benzaldehyde
B
toluene
C
benzoic acid
D
ethyl benzene
Solution:
Toluene, gives different oxidation products, with different oxidizing agents. With
C
r
O
2
C
l
2
, it gives benzaldehyde, while with
K
M
n
O
4
/
H
+
or
K
2
C
r
2
O
7
/
H
+
, it gives benzoic acid.